| Q = | H γ•Cp(t2-t1)•60 |
| Q : | Ventilation volume | [m/min] |
| H : | Heat generation | [kcal/h] |
| γ : | Air specific gravity | 1.2 [kg/m3] |
| Cp : | Air specific heat | 0.24 [kcal/kg• ºC] |
| t1 : | Outdoor temperature | [ºC] |
| t2 : | Indoor temperature | [ºC] |
| (1kW = 860kcal/h) | ||
| Entire ventilation without dryer Model: Z55A4 type |
|
| Heat generation : H | = 55 [kW] × 860 [kcal/h] = 47300 [kcal/h] = t2–t1 = 5 [ ºC] |
◊ Ventilation volume
| Q = | 47300 1.2 × 0.24 × 5 × 60 |
= 547[m3/min] |
◊ Vent window area
| A = | Q 60 × ν × α |
|
Let ν = 2 [m/sec], α = 60 [%]
| A = | 547 60 × 2 × 0.6 |
= 7.6[m2] |
| Local ventilation (duct ventilation) without dryer Model: Z55A |
|
| Heat generation : H | = 55 [kW] × 860 [kcal/h] × 0.05 = 2365 [kcal/h] = t2–t1 = 5 [ºC] |
◊ Ventilation volume
| 2365 | ||
| Q = | = 27.4[m3/min] | |
| 1.2 × 0.24 × 5 × 60 |
◊ Vent window area
| Intake air volume Q1 | = Ventilation volume + Outgoing air volume = 27 + 140 = 167[m3] |
| A = | Q 60 × ν × α |
|
Let ν = 2 [m/sec], α = 60 [%]
| A = | 167 60 × 2 × 0.6 |
= 2.3[m2] |
| Entire ventilation with dryer Model: Z55A |
|
| Heat generation : H | = 55 [kW] × 860 [kcal/h] = 47300 [kcal/h] |
| Dryer DN55 11024 [kcal/h] | = t2–t1 = 5 [ºC] |
◊ Ventilation volume
| Q = | 473000 + 11024 1.2 × 0.24 × 5 × 60 |
= 675[m3/min] |
◊ Vent window area
| A = | Q 60 × ν × α |
|
Let ν = 2 [m / sec], α = 60 [%]
| A = | 675 60 × 2 × 0.6 |
= 9.3[m2] |
| Local ventilation with dryer Model: Z55A |
|
| Heat generation : H | = 55 [kW] × 860 [kcal/h] × 0.05 = 2365 [kcal/h](the natural heat discharge is supposed to be 5%) |
| Dryer DN55 11024 [kcal/h[ | = t2–t1 = 5 [ºC] |
◊ Ventilation volume
| Q = | 2365 + 11024 1.2 × 0.24 × 5 × 60 |
= 155[m3/min] |
◊ Vent window area
| Intake air volumeQ1 | = Ventilation volume + Outgoing air volume = 155 + 140 = 295[m3/min] |
| Q |
|
|||||||
| A = | ||||||||
| 60 × ν × α | ||||||||
Let ν = 2 [m/sec], α = 60 [%]
| A = | 295 60 × 2 × 0.6 |
= 4.1[m2] |